Unit 2 — Force and Translational Dynamics
Why objects move the way they do: systems, forces, free-body diagrams, Newton's three laws, gravity, friction, springs, and circular motion. Each section ends with a short practice set — click "Show answer" to check yourself.
Systems and Center of Mass
A system is an object, or a collection of objects, that you choose to analyze. If you ignore its internal structure, a system can be treated as a single object.
- Internal forces act between objects inside the system. External forces come from outside it.
- Only external forces can change the motion of the system's center of mass.
- The center of mass is the point that moves as if all the mass were concentrated there and all external forces acted on it.
x_cm = (m₁x₁ + m₂x₂ + …) / (m₁ + m₂ + …) a_cm = F_net,external / m_total
- For a uniform, symmetric object, the center of mass is at its geometric center.
- The center of mass does not have to be located on the object (e.g. a ring or a boomerang).
1. A 2 kg mass sits at x = 0 and a 4 kg mass sits at x = 6 m. Where is the center of mass?
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2. Two ice skaters at rest push off each other. Why does their center of mass stay at rest?
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Forces and Free-Body Diagrams
A force is a vector quantity describing an interaction between two objects. Its SI unit is the newton: 1 N = 1 kg·m/s². Forces can be contact (push, tension, friction, normal) or long-range (gravity).
| Force | Symbol | Direction |
|---|---|---|
| Gravitational (weight) | Fg = mg | Toward Earth's center (down) |
| Normal | FN | Perpendicular to the surface, away from it |
| Tension | FT | Along the rope, pulling on the object |
| Friction | Ff | Parallel to the surface, opposing (impending) sliding |
| Spring | Fs | Toward the spring's equilibrium length |
A free-body diagram (FBD) shows all forces acting on one object:
- Draw the object as a dot or box; draw each force as an arrow starting at the object.
- Arrow length reflects magnitude; label every force with its type.
- Include only forces acting on the object, never forces it exerts on others.
- Do not draw the net force, acceleration, or "force of motion" on the FBD.
1. Draw (describe) the FBD for a book at rest on a table.
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2. A block slides down a rough incline. Name the forces on it and their directions.
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Newton's Third Law
Whenever object A exerts a force on object B, B exerts a force on A that has equal magnitude, opposite direction, and is the same type of force.
F(A on B) = − F(B on A)
- The two forces act on different objects, so they never cancel each other on a single FBD.
- Equal forces do not mean equal accelerations.
a = F/m, so the smaller mass accelerates more. - Third-law pairs exist at the same instant, and both forces are of the same kind (gravity pairs with gravity, contact with contact).
1. A heavy truck collides with a small car. Compare the forces each exerts on the other, and compare their accelerations.
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2. A book rests on a table. Is the normal force on the book the third-law partner of the book's weight?
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Newton's First Law
An object keeps its velocity (including a velocity of zero) unless a net external force acts on it. This tendency is called inertia, and mass is its measure.
- If
ΣF = 0, the object is in translational equilibrium: it is at rest or moving at constant velocity. - Motion at constant velocity requires no net force. A net force is needed only to change velocity.
- Equilibrium applies along each axis separately:
ΣFₓ = 0andΣFy = 0.
1. A crate slides across a floor at constant velocity while you push it with 40 N. What is the friction force?
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2. A 2.0 kg block hangs at rest from a rope. What is the tension? (g = 9.8 m/s²)
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Newton's Second Law
The acceleration of a system is directly proportional to the net external force and inversely proportional to its mass, and points in the direction of the net force.
a = ΣF / m ΣFₓ = m·aₓ ΣF_y = m·a_y
Problem-solving steps:
- Choose the system and draw its FBD.
- Pick axes (along the acceleration or along an incline) and resolve forces into components.
- Write
ΣF = mafor each axis, then solve.
- Apparent weight is the normal force you feel. In an elevator accelerating upward at
a:FN = m(g + a); accelerating downward:FN = m(g − a). - Mass is a constant property; weight depends on the local gravitational field.
1. A 4.0 kg block is pulled right with 20 N and left with 8 N. Find its acceleration.
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2. A 60 kg person stands on a scale in an elevator accelerating upward at 2.0 m/s². What does the scale read? (g = 9.8 m/s²)
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Gravitational Force
Every pair of masses attracts each other with a force given by Newton's law of universal gravitation:
F_g = G·m₁·m₂ / r² G = 6.67 × 10⁻¹¹ N·m²/kg² g = G·M / r² (field strength at distance r from mass M)
- Gravity follows an inverse-square law: doubling
rcuts the force to one quarter. ris measured between the centers of the masses.- Near Earth's surface,
Fg = mgwithg ≈ 9.8 m/s². Gravitational mass and inertial mass are numerically equal. - All objects in free fall have the same acceleration
g, regardless of mass, becausemcancels ina = F/m.
1. If the distance between two planets' centers triples, what happens to the gravitational force between them?
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2. A 10 kg object is at a distance of 2R from Earth's center (R = Earth's radius, i.e. one radius above the surface). What is its weight there? (g at surface = 9.8 m/s²)
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Kinetic and Static Friction
Friction is a contact force parallel to the surface that opposes relative sliding between two surfaces.
| Static friction | Kinetic friction | |
|---|---|---|
| When | Surfaces are not sliding | Surfaces are sliding |
| Magnitude | Fs ≤ μsFN (adjusts as needed) | Fk = μkFN (fixed) |
| Direction | Opposes impending sliding | Opposes sliding |
- Typically
μs ≥ μk: it takes more force to start an object moving than to keep it moving. - Friction depends on the normal force and the surfaces, and not on contact area or speed (in this model).
- The normal force is not always
mg. On an incline,FN = mg cos θ; with a vertical pull or push it changes. - Static friction can point in the direction of motion, such as a car's tires pushing the car forward.
1. A 10 kg box slides on a floor with μk = 0.30. What is the kinetic friction force? (g = 9.8 m/s²)
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2. A 20 kg crate (μs = 0.50) is pushed horizontally with 60 N. Does it move? What is the friction force?
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Spring Forces
An ideal spring exerts a restoring force proportional to how far it is stretched or compressed from its equilibrium length. This is Hooke's law:
F_s = − k·x
xis the displacement from equilibrium length;kis the spring constant in N/m (stiffer spring = larger k).- The negative sign means the force always points toward equilibrium.
- On a graph of force vs. displacement, the slope equals k.
- For a mass hanging at rest on a spring:
kx = mg, sox = mg/k.
x is the change in length from the natural length, not the total length of the spring.1. A spring (k = 200 N/m) is stretched 0.15 m. What force does it exert?
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2. A 5.0 N force stretches a spring by 0.10 m. Find k, then find how far the spring stretches when a 2.0 kg mass hangs at rest from it.
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Circular Motion
In uniform circular motion, an object moves in a circle at constant speed. Its velocity is always tangent to the circle, so its direction keeps changing. That means it is accelerating, even though its speed is constant.
a_c = v² / r (toward the center) ΣF_c = m·v² / r (net force toward the center) v = 2πr / T (T = period)
- The centripetal force is not a new kind of force. It is the net force (or component of net force) pointing toward the center, supplied by tension, gravity, friction, a normal force, etc.
- Never draw "centripetal force" as an extra arrow on an FBD.
- If the inward force disappears, the object moves off in a straight line tangent to the circle, not outward.
- Doubling the speed requires four times the centripetal force at the same radius.
| Situation | Provides the centripetal force |
|---|---|
| Ball swung on a string | Tension |
| Car turning on a flat road | Static friction |
| Satellite in orbit | Gravity |
1. A 0.50 kg ball on a string moves in a horizontal circle of radius 2.0 m at 4.0 m/s. Find its centripetal acceleration and the tension.
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2. A car rounds a flat curve of radius 50 m with μs = 0.80. What force provides the centripetal force, and what is the maximum speed without skidding? (g = 9.8 m/s²)