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Study Notes

Unit 3 — Work, Energy, and Power

An energy-based way to analyze motion: kinetic energy, work, potential energy, conservation of energy, and power. Each section ends with a short practice set — click "Show answer" to check yourself.

3.1

Translational Kinetic Energy

Kinetic energy is the energy an object has because of its motion. The SI unit of all energy is the joule: 1 J = 1 kg·m²/s².

K = ½ · m · v²
  • Kinetic energy is a scalar. It is never negative and has no direction.
  • K depends on v²: doubling the speed quadruples the kinetic energy.
  • K depends on the reference frame, because velocity does.
  • The kinetic energy of a system is the sum of the kinetic energies of its parts.
Common mix-up: velocity is squared, so a negative velocity gives positive kinetic energy.
Practice

1. A 2.0 kg cart moves at 3.0 m/s. What is its kinetic energy? What if its speed doubles?

Show answer
K = ½(2.0)(3.0)² = 9.0 J. At 6.0 m/s, K = ½(2.0)(6.0)² = 36 J, four times larger.

2. A 4.0 kg object has 50 J of kinetic energy. How fast is it moving?

Show answer
v = √(2K/m) = √(2·50/4.0) = √25 = 5.0 m/s.
3.2

Work

Work is the transfer of energy to or from a system by a force acting through a displacement. Only the component of force along the displacement does work.

W = F · d · cos θ          (θ = angle between F and displacement)
W_net = ΔK = K_f − K_i      (work–energy theorem)
Angle θWorkEffect on the system
0° (force along motion)PositiveEnergy added (speeds up)
90° (force perpendicular)ZeroNo energy change
180° (force opposes motion)NegativeEnergy removed (slows down)
  • Work is a scalar measured in joules.
  • The normal force on a sliding object and the centripetal force in uniform circular motion do zero work, since they are perpendicular to the motion.
  • On a graph of force vs. position, the area under the curve equals the work done.
  • Kinetic friction does negative work and transfers energy into thermal energy.
Tip: the work–energy theorem uses the net work of all forces. Sum the work of each force, or find Fnet first.
Practice

1. A 10 N force acts at 60° above the horizontal on a crate that moves 5.0 m horizontally. How much work does the force do?

Show answer
W = Fd cos θ = (10)(5.0)(cos 60°) = 25 J.

2. A 2.0 kg object starts from rest and net work of 36 J is done on it. What is its final speed?

Show answer
Wnet = ΔK = ½mv² → v = √(2·36/2.0) = 6.0 m/s.
3.3

Potential Energy

Potential energy is stored energy associated with the arrangement of objects in a system that interact through a conservative force (gravity or a spring). It belongs to the system, not to a single object.

TypeEquationNotes
Gravitational (near Earth)ΔUg = m·g·ΔhOnly the change in height matters; choose any zero level
Elastic (spring)Us = ½·k·x²x = stretch or compression from equilibrium
Gravitational (general)Ug = −G·m₁·m₂ / rZero at infinite separation, so always negative
  • A force is conservative if the work it does depends only on start and end positions, not on the path. Then W = −ΔU.
  • Spring potential energy is the same whether the spring is stretched or compressed by the same amount, since x is squared.
  • The area under an Fs vs. x graph for a spring equals the stored elastic energy.
Key idea: the zero point of potential energy is arbitrary. Only changes in U have physical meaning.
Practice

1. A 3.0 kg book is lifted 4.0 m at constant speed. By how much does the gravitational potential energy of the book–Earth system change? (g = 9.8 m/s²)

Show answer
ΔUg = mgΔh = (3.0)(9.8)(4.0) = 117.6 J (about 118 J).

2. A spring (k = 100 N/m) is compressed 0.20 m. How much energy is stored?

Show answer
Us = ½kx² = ½(100)(0.20)² = 2.0 J.
3.4

Conservation of Energy

Energy cannot be created or destroyed, only transferred between objects or transformed between forms. For any system:

ΔE_system = W_external
Isolated system (no external work, no friction):   K_i + U_i = K_f + U_f
With friction:                                     K_i + U_i − f·d = K_f + U_f
  • Choose the system first. Gravity and springs are internal forces when Earth or the spring is part of the system.
  • Work done by nonconservative forces (friction, applied pushes) changes the total mechanical energy K + U.
  • Friction converts mechanical energy into thermal (internal) energy: ΔEth = fk·d. Total energy is still conserved.
  • Energy methods ignore the path taken, which makes them powerful for curved tracks, pendulums, and roller coasters.

Steps: pick initial and final points, choose a zero level for U, list K and U at each point, add any work by nonconservative forces, and solve.

Common mix-up: mechanical energy is not conserved when friction acts, but total energy (including thermal) always is.
Practice

1. A ball is dropped from rest at a height of 20 m. Ignoring air resistance, what is its speed just before it hits the ground? (g = 9.8 m/s²)

Show answer
mgh = ½mv² → v = √(2gh) = √(2·9.8·20) = ≈ 19.8 m/s. The mass cancels.

2. A 2.0 kg block slides from rest down a ramp, dropping 5.0 m in height. It reaches the bottom at 6.0 m/s. How much energy was converted to thermal energy by friction? (g = 9.8 m/s²)

Show answer
Initial U = mgh = 2.0·9.8·5.0 = 98 J. Final K = ½(2.0)(6.0)² = 36 J. Thermal energy = 98 − 36 = 62 J.
3.5

Power

Power is the rate at which energy is transferred, or equivalently the rate at which work is done. Its SI unit is the watt: 1 W = 1 J/s.

P_avg = W / Δt = ΔE / Δt
P = F · v · cos θ          (instantaneous power for a force on a moving object)
  • Two machines can do the same work, but the one with greater power does it in less time.
  • Power is a scalar.
  • When a force acts along the direction of motion, P = Fv.
  • Another common unit: 1 horsepower ≈ 746 W. A kilowatt-hour (kW·h) is a unit of energy (3.6 × 10⁶ J), not power.
Tip: a bigger motor does not mean more work is needed to lift a load, only that the same work can be done faster.
Practice

1. A student lifts a 50 kg box 3.0 m at constant speed in 5.0 s. What is the average power? (g = 9.8 m/s²)

Show answer
W = mgh = 50·9.8·3.0 = 1470 J. P = W/Δt = 1470/5.0 = 294 W.

2. A car's engine exerts a forward force of 2000 N while the car moves at a constant 20 m/s. What power does the force deliver?

Show answer
P = Fv = 2000 × 20 = 40,000 W (40 kW).